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A charged particle of mass m and charge q is accelerated through a potential difference of V volts. It enters a region of uniform magnetic field which is directed perpendicular to the direction of motion of the particle. Find the radius of circular path moved by the particle in magnetic field.

A

`sqrt(((Vm)/(qB^(2))))`

B

`(2Vm)/(qB^(2))`

C

`sqrt(2qV_(m))((1)/(B))`

D

`sqrt(((Vm)/(q)))((1)/(B))`

Text Solution

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The correct Answer is:
C
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