A gas is at a pressure of 2 atm at 0^(@)...

A gas is at a pressure of 2 atm at `0^(@)` is filled in a container . At what temperature, pressure of gas will be 4 atm?

A

514 k

B

546 k

C

612 k

D

653 k

Text Solution

Verified by Experts

The correct Answer is:

B

Let, initial pressure `p_(1)=2 atm`
Initial temperature `T_(1)=0^(@)C+273=273K`
Then according to Gay-Lussac's law
`p_(1)/T_(1)rArrT_(2)=(p_(2)xxT_(1))/p_(1)=(4xx273)/2=546 k`

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