The oxidation states of S atom in `S_(4)O_(6)^(2-)` from left to right respectively are
`O-underset(O)underset(||)overset(O)overset(||)S-S-S-underset(O)underset(||)overset(O)overset(||)S-O`

Options

A. `+3,+1, +1, +3`
B. `+4, +1, +1, +4`
C. `+5, 0, 0, +5`
D. `+6, 0, 0, +6`

Answer

C

Explanation

Corner S-atom, +2 each from (=0), +1 from `(O^(-))` and zero from `-S`. Therefore, its oxidation number is `+5`. Middle S atoms has 0 oxidation number.