`I^(-)` reduces `IO_(3)^(-)` to `I_(2)` and itself oxidised to `I_(2)` in acidic medium. Thus, final reaction is

Options

A. `I^(-) + IO_(3)^(-) + 6H^(+) to I_(2) + 3H_(2)O`
B. `I^(-) + IO_(3)^(-) to I_(2) + O_(3)`
C. `5I^(-) + IO_(3)^(-) + 6H^(+) to 3I_(2) + 3H_(2)O`
D. None of the above

Answer

C

Explanation

`5I^(-) + IO_(3)^(-) + 6H^(+) to 3I_(2) + 3H_(2)O`