For the redox reaction, `MnO_(4)^(-) + C_(2)O_(4)^(2-) + H^(+) rarr Mn^(2+) + CO_(2) + H_(2)O` the correct coefficients of the reactants for the balanced reaction are

Options

A. `{:(MnO_(4)^(-),C_(2)O_(4)^(2-),H^(+)),(2,5,16):}`
B. `{:(MnO_(4)^(-),C_(2)O_(4)^(2-),H^(+)),(16,5,2):}`
C. `{:(MnO_(4)^(-),C_(2)O_(4)^(2-),H^(+)),(5,16,2):}`
D. `{:(MnO_(4)^(-),C_(2)O_(4)^(2-),H^(+)),(2,16,5):}`

Answer

D

Explanation

`MnO_(4)^(-) + 8H^(+) + 5e^(-) to Mn^(2+) + 4H_(2)O xx 2`
`" " C_(2)O_(4)^(2-) to 2CO_(2) + 2e^(-) xx 5`
`bar(MnO_(4)^(-) + 5Cr_(2)O_(4)^(2-) + 16H^(+) to 2Mn^(2+) + 10 CO_(2) + 8H_(2)O`
Thus, the coefficients of `MnO_(4)^(-), C_(2)O_(4)^(2-)` and `H^(+)` in the above balance equation respectively are 2,5, 16.