Given : Dipole moment of `HCl=1.03` D
Bond length of `HI=0.38D`
Bond length `=161`pm
The ratio of partial positive charge on H-aotm in HCl to that in HI will be

Options

A. `2:1`
B. `3.42:1`
C. `2.39:1`
D. `4:1`

Answer

B

Explanation

Dipole moment `(mu)= qxxd`
`or q=(mu_(HCl))/(d) S=(1..03xx10^(-18))/(127xx10^(-10) cm)`
`=0.81xx10^(-19)` esu
Fractional charge `(delta)=(q)/(e)=(0.81xx10^(-10) esu)/(4.8xx10^(-1) esu)=0.168`
Dipole moment `mu_(Hl)=(0.38xx10^(-18) "esu cm")/(161xx10^(-19) cm)`
`=0.236xx10^(-10) esu`
Fractional charge `(delta)=(0.236xx10^(-10)esu)/(4.8xx10^(-19)esu)`
`=0.049`
Ratio of partial positive charge on HCl and Hl
`=(0.168)/(0.049_=3.42:1`