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The bond order of H(2)^(-) ion is (1)/(2...

The bond order of `H_(2)^(-)` ion is `(1)/(2)`. If it has 2 bonding electrons, how many antibonding electrons it will have ?

A

3

B

1

C

2

D

4

Text Solution

Verified by Experts

The correct Answer is:
B
As bond order `=(1)/(2)(N_(b)-N_(a))`
`:. N_(a)=N_(b)-2xx ` bond order
`=2-2xx(1)/(2) or N_(a)=1`
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