The normality of a solution formed by mixing 0 . 45 N and 0 . 60 N N OH in the ratio of `2:1` by volume is

Options

A. 0.15 N
B. 0.8 N
C. 0.5 N
D. 0.45 N

Answer

C

Explanation

`"Given, normality of Na Oh"=0.45 " N"and 0.60 N`
`"Total volume of the solution" =2V+V=3V`
`"Total gram-equivalents of NaOh solution obtained"=Nxx3V`
`"Thus", Nxx3V=(0.45xx2V)+(0.6V),N=(1.5V)/(3V)=0.5N`