What is the volume of water consumed during acid hydrolysis of 1.368 kg of surose ?

Options

A. `0.072dm^(3)`
B. `0.720dm^(3)`
C. `0.18dm^(3)`
D. `0.018dm^(3)`

Answer

A

Explanation

`underset(342g)("Sucrose")+underset(18g)(H_(2)O)tounderset(180g)underset("Glucose")(C_(6)H_(12)O_(6))+underset(180g)underset("Fructose")(C_(6)H_(12)O_(6))`
`because342g" sucrose consume"=18gH_(2)O`.
`:.lg" sucrose consume "=(18)/(342)gH_(2)O`
`:.1.368xx1000g" sucuose consume"`
`=(18)/(342)xx1.368xx1000`
`=72gH_(2)O`
Now, given density of `H_(2)O=1g//cm^(3)`
`"Density d"=(m)/(v)`
`V=(m)/(d)=(72g)/(1g//cm^(3))=72cm^(3)`
`0.072dm^(3)`