`2.5 cm^(3)` of `0.2 M H_(2)SO_(4)` solution is diluted to 0.5 `dm^(3)` . Find normality of the diluted solution .

Options

A. `0.2N`
B. `0.02N`
C. `0.002N`
D. `0.04N`

Answer

C

Explanation

`V_(1)=2.5cm^(3)=2.5xx10^(-3)dm^(3)`,
`V_(2)=0.5dm^(3)`
`=0.2M=0.4N" "[because1N=2M]`
`underset(("before dilution"))(N_(1)V_(1))" = "underset(("after dilution"))(N_(2)V_(2))`
`2.5xx10^(-3)xx0.4=N_(2)xx0.5`
`:.N_(2)=(2.5xx10^(-3)xx0.4)/(0.5)=0.002N`