The volume of 2N `H_(2)SO_(4)` solution is `0.1dm^(3)`. The volume of its decinormal solution (in `dm^(3)`) will be

Options

A. `0.1`
B. `0.2`
C. `2`
D. `1.7`

Answer

C

Explanation

For solution of same substance,
`N_(1)V_(1)=N_(2)V_(2)`
`rArr2Nxx0.1=(N)/(10)xxV_(2)`
`rArrV_(2)=2dm^(3)`