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The freezing point of a 0.05 molal solut...

The freezing point of a `0.05` molal solution of a non-electrolyte in water is:
(`K_(f) = 1.86 "molality"^(-1)`)

A

`-0.093^(@)C`

B

`1.83^(@)C`

C

`0.93^(@)C`

D

`0.093^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
A
For non-electrolyte
`DeltaT_(f)=K_(f)xxm`
`"Given",m=0.05,`
`:.DeltaT_(f)=1.86xx0.05=0.093^(@)C`
Freezing point of solution
`=0.-DeltaT_(f)=0-0.093`
`=-0.093^(@)C`
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