0.15g of a subatance dissolved in 15g of...

`0.15`g of a subatance dissolved in `15`g of solvent boiled at a temperature higher at `0.216^(@)`than that of the pure solvent. Calculate the molecular weight of the substance. Molal elecation constant for the solvent is `2.16^(@)C`

100

`10.1`

`1.001`

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The correct Answer is:

`m=(K_(b)xxwxx1000)/(DeltaT_(b)xxW)`
`=(21.16xx0.15xx1000)/(0.216xx15)=100`

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