`DeltaU^(@)` for combustion of methane is -X kJ `mol^(-1)`. The value of `DeltaH^(@)` is

Options

A. `=DeltaU^(@)`
B. `gtDeltaU^(@)`
C. `lt DeltaU^(@)`
D. `=0`

Answer

C

Explanation

`CH_(4)(g)+2O_(2)(g) to CO_(2)(g)+2H_(2)O(l)`
`Deltan_(g)=(n_(p)-n_(r))=1-3=-2`
`DeltaH^(@)=DeltaU^(@)+Deltan_(g)RT=-X-2RT`
Hence, `DeltaH^(@) lt Delta U^(@)`