For the given reaction,
`CH_(4)(g)+2O_(2)(g)toCO_(2)(g)+2H_(2)O(l)`
Select the correct option for `Delta_(r)H`.

Options

A. `[H_(m)(CO_(2),g)+2H_(m)(O_(2),g)]-[2H_(m)(H_(2)O,l)+H_(m)(CH_(4),g)]`
B. `[2H_(m)(O_(2),g)+H_(m)(CH_(4),g)]-[H_(m)(CO_(2),g)+2H_(m)(H_(2)O,l)]`
C. `[H_(m)(CO_(2),g)+2H_(m)(H_(2)O,l)]-[H_(m)(CH_(4),g)+2H_(m)(O_(2),g)]`
D. `[H_(m)(CO_(2),g)+H_(m)(H_(2)O,l)]-[H_(m)(CH_(4),g)+2H_(m)(O_(2),g)]`

Answer

C

Explanation

`CH_(4)(g)+2O_(2)(g) to CO_(2)(g)+2H_(2)O(l)`
`Delta_(r)H=underset(i)(sum)sigma_(i)H_("products")-underset(i)(sum)sigma_(i)H_("reactants")`
`=[H_(m)(CO_(2),g)+2H_(m)(H_(2)O,l)]-[H_(m)(CH_(4),g)+2H_(m)(O_(2),g)]`
where, `H_(m)` is the molar enthalpy.