Home
Class 12
CHEMISTRY
When one mole of monoatomic ideal gas at...

When one mole of monoatomic ideal gas at T temperature undergoes adiabatic change under a constant external pressure of 1 atm, change in volume is from 1 L to 2L. The final temperature in kelvin would be

A

`(T)/(2^((2//3)))`

B

`T+(2)/(3xx0.0821)`

C

`T`

D

`T-(2)/(3xx0.0821)`

Text Solution

Verified by Experts

The correct Answer is:
A
`(T)/(T_("final"))=((V_(2))/(V_(1)))^(gamma-1)=((2)/(1))^((5//3-1))`
`=2^((2//3)),T_("final")=(T)/(2^((2//3)))`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CHEMICAL THERMODYNAMICS AND ENERGETIC

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise MHT CET Corner|40 Videos

  • CHEMICAL THERMODYNAMICS AND ENERGETIC

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise Exercise 1|88 Videos

  • CHEMICAL KINETICS

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise MHT CET CORNER|20 Videos

  • CHEMISTRY IN EVERYDAY LIFE

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise MHT CET CORNER|11 Videos

Similar Questions

Explore conceptually related problems

A mole of a monoatomic ideal gas at 1 atm and 273 K is allowed to expand adiabatically against a constant pressure of 0.395 bar will until equilibrium is reached. (a) What is the final temperature ? (b) What is the final volume ? (c ) How much work is done by the gas ? (d) What is the change in internal energy ?

One mole of monoatomic ideal gas at T(K) is exapanded from 1L to 2L adiabatically under constant external pressure of 1 atm . The final tempreture of gas in kelvin is

Knowledge Check

  • When one mole of monoatomic ideal gas at T K undergoes adiabatic change under a constant external pressure of 1 atm changes volume from 1 litre to 2 litre. The final temperature in Kelvin would be

    A
    `(T)/(2^((2//3)))`
    B
    `T+(2)/(3xx0.0821)`
    C
    T
    D
    `T-(2)/(3xx0.0821)`

  • When one mole of monoatomic ideal gas at T K undergoes adiabatic change under a constant external pressure of I atm and volume changes from 1 litre to 2 litre. The final temperature in Kelvin would be

    A
    `T/(2^((2//3)))`
    B
    `T+2/3xx0.0821`
    C
    T
    D
    `T-2/3xx0.0821`

  • When 1mol of a monoatomic ideal gas at TK undergoes adiabatic change under a constant external pressure of 1atm , changes volume from 1 L to 2L . The final temperature (in K) would be

    A
    `(T)/(2^(2//3))`
    B
    `T +(2)/(3xx0.0821)`
    C
    `T`
    D
    `T -(2)/(3 xx 0.0821)`

    • Similar Questions

    Explore conceptually related problems

    One mole of an ideal monoatomic gas at temperature T and volume 1L expands to 2L against a constant external pressure of one atm under adiabatic conditions, then final temperature of gas will be:

    One mole of an ideal monoatomic gas at temperature T and volume 1 L expands to 2 L against a constant external pressure of one atm under adibatic conditions, then final temperature of gas will be :

    One mole of an ideal monoatomic gas at 27^(@) C expands adiabatically against constant external pressure of 1 atm from volume of 10 dm^(3) to a volume of 20 dm^(3) .

    When one mole of a monoatomic ideal gas at initial temperature T K expands adiabatically from 1 litre to 2litres , the final temperature in Kelvin would be

    250L of an ideal gas is heated at constant pressure from 27%(@)C such that its volume becomes 500L . The final temperature is

    Home
    Profile