When one mole of monoatomic ideal gas at T temperature undergoes adiabatic change under a constant external pressure of 1 atm, change in volume is from 1 L to 2L. The final temperature in kelvin would be

Options

A. `(T)/(2^((2//3)))`
B. `T+(2)/(3xx0.0821)`
C. `T`
D. `T-(2)/(3xx0.0821)`

Answer

A

Explanation

`(T)/(T_("final"))=((V_(2))/(V_(1)))^(gamma-1)=((2)/(1))^((5//3-1))`
`=2^((2//3)),T_("final")=(T)/(2^((2//3)))`