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The equilibrium constannt of a reaction ...

The equilibrium constannt of a reaction is 0.008 at 298 K. the standard energy change of the reaction at the same temperature is

A

`-11.96kJ`

B

`-5.43kJ`

C

`-8.46kJ`

D

`+11.96kJ`

Text Solution

Verified by Experts

The correct Answer is:
D
Standard free energy change,
`DeltaG^(@)=-2.303RTlogK_(c)`
`=-2.303xx8.314xx298xxlog` 0.008
`=+11965.16J=11.96kJ`
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-CHEMICAL THERMODYNAMICS AND ENERGETIC-Exercise 2
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