The value of enthalpy change `(DeltaH)` for the reaction `C_(2)H_(5)OH(l)+3O_(2)(g)to2CO_(2)(g)+3H_(2)O(l)`, at `27^(@)C` is `-1366.5" kJ "mol^(-1)`. The value of internal energy change for the above reaction at this temperature will be

Options

A. `-1371.5kJ`
B. `-1369.0kJ`
C. `-1364.5kJ`
D. `-1361.5kJ`

Answer

C

Explanation

`DeltaH=DeltaE+Deltan_(g)RT`
where, `Deltan_(g)=`Number of moles of gaseous products-no. of moles of gaseous reactants
=2-3=-1
`implies -1365.5=DeltaE-1xx8.314xx10^(-3)xx300`
`DeltaE=-1364.0" kJ "mol^(-1)`