In view of the signs of `DeltaG^(ө)` for the following reactions,
`PbO_(2)+Pb to 2PbO,Delta_(r)G^(ө) lt 0`,
`SnO_(2)+Snto 2SnO,Delta_(r)G^(ө) gt 0`
Which oxidation states are more characteristic for lead and tin?

Options

A. For lead +4, for tin +2
B. For lead +2, ffor tin +2
C. For lead +4, for tin +4
D. For lead +2, for tin +4

Answer

D

Explanation

`overset(+4)(Pb)O_(2)+overset(0)(Pb) to 2 overset(+2)(Pb)O`
Since, `Delta_(r)G^(@) lt 0`, hence +2 state of lead is favourable.
`overset(+4)+(Sn)O_(2)+overset(0)(Sn) to 2 overset(0)(Sn)O`
Since, `Delta_(r)G^(@)gt0` it means forward reaction is not spontaneous.
`2overset(+2)(Sn)O+overset(+4)(Sn)O_(2) to 2overset(0)(S)n`
`Delta_(r)G^(@) lt0`, thus +4 state of tin is favourable.