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What is the equilibrium constant, K for ...

What is the equilibrium constant, K for the following reaction at 400 K?
`2NOCl (g) hArr 2NO(g)+Cl_(2)(g)`
`DeltaH=77.2" kJ "mol^(-1) and DeltaS=122JK^(-1)mol^(-1)` at 400K.

A

`-3.708`

B

`1.95xx10^(-4)`

C

`2.8xx10^(4)`

D

`1.67xx10^(-5)`

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaG=DeltaH-TDeltaS`
`=77.2-400xx122xx10^(-3)`
`=+28.4kJ" "mol^(-1)=28400" J "mol^(-1)`
Further, `DeltaG=-2.303RTlogK`
or `28400=-2.303xx8.314xx400xxlogK`
`logK=-(28400)/(2.303xx8.314xx400)`
`logK=-3.708`
`K=`Antilog (-3.708)`=1.95xx10^(-4)`
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