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The work done when two moles of an ideal...

The work done when two moles of an ideal gas is compressed from a volume of `5m^(3)` to `1dm^(3)` at 300 K, under a pressure of 100 kPa is

A

`499.9 kJ`

B

`-499.9kJ`

C

`-99.5kJ`

D

`42495kJ`

Text Solution

Verified by Experts

The correct Answer is:
A
Work done,
`W=-p_(ext)(V_(2)-V_(1))`
Here, `p_(ext)=100kPa`
`implies V_(2)=1dm^(3)=1L`
`therefore W=-100xx(1-500)`
`=499900` kPa L
`499900J=499.9kJ" "(because1kPaL=1kJ)`
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