The unit `"mol L"^(-1)s^(-1)` is meant for the rate constant of the reaction having the order

Options

A. 0
B. 2
C. 1
D. 3

Answer

A

Explanation

General unit for rate constant = `(("mol")/(L))^(1-n)s^(-1)`
(where , n=order of reaction )
Given , unit for rate constant =`(("mol")/(L))s^(-1)`
On comparing , `(("mol")/(L))^(1-n)s^(-1) =(("mol")/(L))s^(-1) `
1-n=1
`therefore " "n=0 `
Hence, the order of reaction is zero.