The rate constant for the first order reaction is `60 s^(-1)`. How much time will it take to reduce the concentration of the reactant to `1//16th` value ?

Options

A. 0.046 s
B. 0.025 s
C. 0.098 s
D. 0.060 s

Answer

A

Explanation

For first order reaction ,
`t=(2:303)/(k)"log"(a)/((a-x)) " "cdots(i)`
Given,`(a-x)=(a)/(16),k=60^(-1)`
On substituting the valuse in Eq. (i),
`t=(2.303)/(60s^(-1))"log"(axx16)/(a)=(2.303)/(60s^(-1))"log"16=(2.303)/(60s^(-1))"log"2^(4)`
`=(2.303)/(60s^(-1))xx4"log"2=(2.303)/(60s^(-1))"xx4xx0.3010`
`=4.62xx10^(-2)s`
Time=0.046s