The half life period of a substance is 50 minutes at a certain initial concentration. When the concentration is reduced to one half of the initial value, the half-life period is 25 minutes. Calculate the order of the reaction.

Options

A. 0
B. `(1)/(2)`
C. `(3)/(2)`
D. 2

Answer

C

Explanation

We knon that ,`t(t//2)propC^(1-n)` (Where, n is the order of reaction )
`therefore" "((t//2))/((t//2))=(C_(1)/C_(2))^(1-n)`
or `" "` `(50)/(25)=((C)/(4C))^(1-n) or 2=((1)/(2))^(1-n)`
or `" "` `2=(2)^(2n-2) or 2n-2=1`
Hence, the order of reaction `=(3)/(2)`