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The decomposition of hydrocarbon follow...

The decomposition of hydrocarbon follows the equation `k=(4.5xx10^(11)s^(-1))e^(-28000K//T)`
Calculate `E_(a)`.

A

`232.79 " ""kJ mol"^(-1)`

B

`425.25 " ""kJ mol"^(-1)`

C

`300" ""kJ mol"^(-1)`

D

`885.2" ""kJ mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A

According to Arrhenius equation,
`k=Ae^(-E_a//RT)`
According to the availlable data
`k=(4.5xx10^(11)s^(-1))xxe^(28000K//T)`
On comparing both equations,
`- E_(a)/(RT)=(-28000K)/(T) `
`E_(a) =(28000K)xxR`
`=(28000K)xx(8.314JK^(-1)"mol"^(-1))`
232792J`"mol"^(-1)`
`E_(a)=232.792KJ"mol"^(-1)`
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-CHEMICAL KINETICS -Exercise 1
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  8. A first order reaction is 10% complete in 20 min. the time taken for 1...

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  9. For a zero order reaction, the integrated rate equation is

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  11. The integrated rate equation is kt= "log" C(0)-"log"C(t). The stra...

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  12. On the basis of Arrhenius equation, consider the following statement (...

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  13. What will happen, on increasing the temperature or decreasing the act...

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  14. The potential energy diagrams for four reaction are given below W...

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  15. Rate constant k of a reaction is dependent on temperatur: k=Ae^(Ea//...

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  16. In the graph of Arrhenius equation , the intercept and slope are

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  17. The rate constant of a reaction is given by k = 2.1 xx 10^(10) exp(-27...

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  18. Rate of a reaction can be expressed by Arrhenius equation as: k = Ae...

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  20. The activation energy for a reaction at temperature T K was found to b...

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