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The rate law for the reaction RCl + Na...

The rate law for the reaction
`RCl + NaOH(aq) rarr ROH + NaCl` is given by
Rate `= k[RCl]`. The rate of the reaction will be

A

is doubled by doubling the concentration of NaOH

B

is halved by reducing the concentration of RCI by one half

C

is increased by increasing the temperature of the reaction

D

is unaffected by change in temperature

Text Solution

Verified by Experts

The correct Answer is:
B
`RCI+NaOHrarrROH+NaCI`
Rate = `k[RCI]`
For this reaction, rate of reaction depends upon the concentration of RCI. It means, the rate of reaction is halved by reducing the concentration of RCI by one half.
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