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The rate constant (K') of one reaction i...

The rate constant `(K')` of one reaction is double of the rate constant (K") of another reaction. Then the relationship between the corresponding activation energies of the two reactions `(E_(a)^(') "and" E_(a)^(''))` will be

A

`E_(a)gtE_(a) `

B

`E_(a)'=4E`

C

`E_(1)=E_(a)`

D

`E_(a)lt E_(a)`

Text Solution

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The correct Answer is:
D

Rate constant (k)`gt` rate constant (k)
Greater the rate constant lesser will be the activation energy,
`:." "E_(a)ltE_(a) `
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-CHEMICAL KINETICS -Exercise 2
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