consider the following reaction,
`N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g)`
The rate of change of concentration for nitrogen is `-0.3xx10^(-4)Ms^(-1).` The rate of change of concentration of ammonia is

Options

A. `0.2xx10^(-4)Ms^(-1)`
B. `0.4xx10^(-4)Ms^(-1)`
C. `0.6xx10^(-4)Ms^(-1)`
D. `-0.6xx10^(-4)Ms^(-1`

Answer

C

Explanation

`N_(2)(g)+3H_(2)(g)hArr 2NH_(3)(g)`
Rate of reaction `=-(d[N_(2)])/(dt)=(1)/(2)(d(NH_(3)))/(dt)`
`:." "(d[NH_(3)])/(dt)=-2(d[N_(2)])/(dt)`
`=-2(-0.3xx10^(-4)Ms^(-1))`
`0.6xx10^(-4)Ms^(-1)`