Consider the following reaction,
`2P_(2)O_(5)rarr4PO_(2)(g)+O_(2)(g)`
If the concentration of PO_(2) increases by `5.2xx10^(-3)M` in 100 s, the rate of a reaction is

Options

A. `0.5xx10^(-4)Ms^(-1)`
B. `2.5xx10^(-5)Ms^(-1)`
C. `1.3xx10^(-5)Ms^(-1)`
D. `2xx10^(3)Ms^(-1)`

Answer

C

Explanation

Rate of reaction = `(1)/(4)(d[PO_(2)])/(dt)=(1)/(4)xx(5.2xx10^(-3)M)/(100s)`
`=1.3xx10^(-5)Ms^(-1)`