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Consider the following reaction, N(2)(...

Consider the following reaction,
`N_(2)(g)+3H_(2)(g)hArr 2NH_(3)(g)+22kcal" mol"^(-1)`
The activation energy for the forward reaction is 50 kcal. What is the activation energy for the backward reaction?

A

`-28kcal" mol"^(-1)`

B

`+28kcal"mol"^(-1)`

C

`-72kcal"mol"^(-1)`

D

`+72kcal" mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
The activation energy for forward reaction
`=50kcal" mol"^(-1)`
Energy released during the reaction =`22"kcal mol"^(-1)`
Therefore, the acativation energy for the backward reaction `=50+22"kcal"=72"kcal mol"^(-1)`
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-CHEMICAL KINETICS -Exercise 2
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