For the second order reaction,
`A+Brarr"products"`
when a moles of A react with b moles of B, the rate equation is given by
`k_(2)t=(1)/(a-b)In(b(a-x))/(a(b-x))`
when `agtgtb,` the rate expression becomes that of

Options

A. first order
B. zero order
C. unchanged, second order
D. third order

Answer

A

Explanation

`A+Brarr"products"`
when `agtgtb` i.e. reactant A is present in large excess, the rate of reactant will not depend upon its concentration.
Hence, it will be of first order.