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The initial rate, -(d[A])/(dt) at t=o wa...

The initial rate, `-(d[A])/(dt)` at t=o was found to be `2.6xx10^(2)" mol "L^(-1)s^(_1)` for the reaction
`A+2Brarr"products"`
The initial rate, `-(d[B])/(dt),` at t=o is

A

`0.10" mol "L^(-1) s^(-1)`

B

`2.6xx10^(2)" mol "L^(-1)s^(-1)`

C

`5.2xx10^(2)" mol "L^(-1)s^(-1)`

D

`6.5xx10^(-3)" mol " L^(-1)s^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C

`A+2B rarr ` Products From rate law,
`-(d[A])/(dt)=-(1)/(2)(d[B])/(dt)`
`therefore" "(d[B])/(dt)=2(d[A])/(dt)=2xx2.6xx10xx-2`
`=5.2xx10^(-2)mol L^(-1)s^(-1)`
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-CHEMICAL KINETICS -Exercise 2
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