Rate law for the reaction `A + B to ` product is rate `=K [A]^(2) [B].` What is the rate of reaction at a given temperature is `0.22Ms^(-1)` , when [A]=1 M and [B]=0.25 M?

Options

A. `3.52M^(-2)s^(-1)`
B. `0.88M^(-2)s^(-1)`
C. `1.136M^(-2)s^(-1)`
D. `0.05M^(-2)s^(-1)`

Answer

B

Explanation

For reaction,
`A+BrarrProduct`
`dx/dt=k[A]^(2)[B]Rightarrow0.22=k(1)^(2)0.25`
`therefore" "k=0.22/0.22=0.88" "M^(-2)s^(-1)`