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On treating PCl(5) with H(2)SO(4), sulph...

On treating `PCl_(5)` with `H_(2)SO_(4)`, sulphuryl chloride `(SO_(2)Cl_(2))` is formed as the final product. This shows that `H_(2)SO_(4)`

A

has two hydroxyl groups in its structure

B

is a derivative of sulphur dioxide

C

is a dibasic acid

D

has greater affinity for water

Text Solution

Verified by Experts

The correct Answer is:
A
`PCl_5+HO-underset(O)underset(||)overset(O)overset(||)S-OH toCl-underset(O)underset(||)overset(O)overset(||)S-Cl+POCl_(3)+H_(2)O`
`PCl_(5)` attacks -OH group and replace it by -Cl group . Hence , reaction of `PCl_(5)` with `H_2SO_(4)` shows the presence of two -OH groups in `H_2SO_4` .
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  1. Which one of the following compounds has the smallest bond angle in i...

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  2. Number of sigma bonds in P4 O(10) is :

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  7. The number of P-O-P bonds in cyclic metaphosphoric acid is.

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  8. Consider the following compounds : (i) sulpher dioxide (ii) hydrog...

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  12. Ammonia , on reaction with hypochlorite anion, can form

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  13. The percentage of p-character in the orbitals forming p-p bonds in P4 ...

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  14. The reason why conc. H2SO4 is used extensively to prepare other acids ...

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  16. Which of the following statements regarding ozone is not true?

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  17. Which of the following salt would give SO2 with hot and dil. H2 SO4 an...

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  18. In which cases, the order of acidic strength is not correct ?

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  19. Which of the following dissolves in water but does not give any oxya...

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  20. Identify the incorrect statement among the following.

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