The transition metal ion that has 'spin -only ' magnetic moment value of 5.96 is

Options

A. `Fe^(2+)`
B. `Cu^(2+)`
C. `Mn^(2+)`
D. `V^(2+)`

Answer

C

Explanation

Given, `mu=5.96`BM
The magnetic moment is given by
`mu-sqrt(n(n+2))BMimplies5.96=sqrt(n(n+2))BM`
on solving for 'n', we get, `n=5`
Therefore, given value of `mu_(("spin"))` is shown by `Mn^(2+)` ion, because `Mn^(2+)` ions has five unpaired electrons.