What is the correct roder of spin only magnetic moment (in BM) of `Mn^(2+), Cr^(2+) and Ti^(2+)`?

Options

A. `Mn^(2+)gtTi^(2+)gtCr^(2+)`
B. `Ti^(2+)gtCr^(2+)gtMn^(2+)`
C. `Mn^(2+)gtCr^(2+)gtTi^(2+)`
D. `Cr^(2+)gtTi^(2+)gtMn^(2+)`

Answer

C

Explanation

Spin only magnetic moment depends upon the number of unpaired electrons. More the number of unpaired electrons, grater will be the spin only magnetic moment. `._(25)Mn=1s^(2),2s^(2)2p^(6),3s^(2),3p^(6),3d^(5),4s^(2)`
`Mn^(2+)=1s^(2),2s^(2)2p^(6),3s^(2),3p^(6),3d^(5),4s^(0)`

Number of unpaired electrons=5 `._(24)Cr=1s^(2),2s^(2),2p^(6),3s^(2),3p^(6),3d^(5),4s^(1)`
`Cr^(2+)=1s^(2),2s^(2),2p^(6),3s^(2),3p^(6),3d^(4),4s^(0)`

Number of unpaired electrones =4
`._(22)Ti=1s^(2),2s^(2),2p^(6),3s^(2),3p^(6)3d^(2),4s^(2)`
`Ti^(2+)=1s^(2),2s^(2),2p^(6),3s^(2),3p^(6),3d^(2),4s^(0)`

Number of unpaired electrons=2 So , the correct order of spin only magnetic moment is
`Mn^(2+)gtCr^(2+)gtTi^(2+)`