When Kl (excess) is added to
(I)`CuSO_(4)` ,
(II) `HgCl_(2)`
(III) `Pb(NO_(3)_(2))`

Options

A. a white ppt. of cul in I, an orange ppt. of `Hgl_(2)` in II and a yellow ppt. of `Pbl_(2)`in III
B. a white ppt. of `Cul_(2),Hgl_(2) and a yellow ppt. of `Pbl_(2)` in III
C. a white ppt. of `Cul_(2), Hgl_(2)` and `Pbl_(2)`
D. None of the above

Answer

A

Explanation

(I)`2CuSO_(4)+4Klrarrunderset("White ppt.")(Cu_(2)l_(2))+l_(2)+2K_(2)SO_(4)`
(II) `HgCl_(2)+2Klrarr2KCl+underset("Orange ppt.")(Hgl_(2)darr``Hgl_(2)+2Klrarrunderset("soluble")(K_(2)Hgl_(4))`
(III) `Pb(NO_(3))_(2)+2Klrarrunderset("yellow ppt")(Pbl_(2)darr)+2KNO_(3)`