the caculated magnetic moment of a divalent ion of an atomic number 24 in aqueous solution is

Options

A. 4.90BM
B. 5.92BM
C. 2.87BM
D. 1.73BM

Answer

A

Explanation

`._(24)M=1s^(2),2s^(2),2p^(6),3s^(2),3p^(6),3d^(5),4s^(1)`
` M^(2+)=[Ar]3d^(4)`

`therefore` Number of unpaired electronic =4
`therefore` Magnetic moment, `mu=sqrt(n(n+2))`
`mu=sqrt(4(4+2))=sqrt24=4.90`BM