Among the following series of transition metal ions, the one in which all metal ions have `3d^(2),3p^(6)` electronic configuration is (Atomic no. of `Ti=22,V=23,Cr=24,Mn=25`)

Options

A. `Ti^(+),V^(2+),Cr^(3+),Mn^(4+)`
B. `Ti^(+),V^(4+),Cr^(6+),Mn^(7+)`
C. `Ti^(4+),V^(3+),Cr^(2+),Mn^(3+)`
D. `Ti^(2+),V^(3+),Cr^(4+),Mn^(5+)`

Answer

D

Explanation

`Ti^(2+)=1s^(2),2s^(2),2p^(6),3s^(2),3p^(6),3d^(2),4s^(0)`
`V^(3+)=1s^(2),2s^(2),2p^(6),3s^(2),3p^(6),3d^(2),4s^(0)`
`Cr^(4+)=1s^(2),2s^(2),2p^(6),3s^(2),3p^(6),3d^(2),4s^(0)`
`Mn^(5+)=1s^(2),2s^(2),2p^(6),3s^(2),3p^(6),3d^(2),4s^(0)`