Amongst the following, the lowest degree of paramgnetism per mole of the compound at `298 K` will be shown by

Options

A. `MnSO_(4).4H_(2)O`
B. `NiSO_(4).6H_(2)O`
C. `FeSO_(4).6H_(2)O`
D. `CuSO_(4).5H_(2)O`

Answer

D

Explanation

In `MnSO_(4). 4H_(2)O`, Mn is present as `Mn^(2+)`

(unpaired electrons=5)
In`CuSO_(4).5H_(2)O,Cu` is present as `Cu^(2+)`

(unpaired electrons=1)
In` FeSO_(4).6H_(2)O`, Fe is present as `fe^(2+)`

(unpaired electrons =4)
In `NiSO_(4). 6H_(2)O`, Ni is present as `Ni^(2+)`

(unapired electrons=2)
Since, paramagnetic character `prop` unpaired electrons. Thus, `CuSO_(4).5H_(2)O` has the lowest degree of paramagnetism among the given at 298K.