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When Zn is treated with excess of NaOH, ...

When Zn is treated with excess of NaOH, the product obtained is

A

`Zn(OH)_(2)`

B

`ZnOH`

C

`Na_(2)ZnO_(2)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
When Zn reacts with excess of NaOH, sodium zincate is obtained.
`Zn+2NaOH+2H_(2)OrarrNaunderset("soluble")([Zn(OH))_(4)]+H_(2)` or
`Zn+2NaOH+2H_(2)OrarrNa_(2)ZnO_(2)+2H_(2)O+H_(2)`
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