Which one of the following is wrongly matched ?

Options

A. `[Cu(NH_(3))_(4)]^(2+)-` square planar
B. `[Ni(CO)_(4)]-`Neitral ligand
C. `[Fe(CN)_(6)]^(3-)-Sp^(3)d^(2)`
D. `[Co(en)_(3)]^(3+)-` Follows EAN rule

Answer

C

Explanation

In `[Cu(NH_(3))_(4)]^(2+)`,
` Cu` is present as `Cu^(2+)`
` Cu^(2+)=[Ar] 3d^(9)4S^(0)`

` implies ` square planar geometry
in `[Ni(CO)_(4),` Co is a neutralligand
in `[Fe(CN)_(6)]^(3-) ` , Fe is present as `Fe ^(3+)`
` Fe^(3+)=[Ar]3d^(5)4s^(0)`
` [Fe (CH)_(6)]^(3-)`
` (##ARH_EGN_PRG_C18_E01_056_S02.png" width="80%">
thus , its hybridisation is `d^(2) Sp^(3) ` , not `SP^(3) d^(2) ` i. e it is is an inner orbital complex .
`[Co (en)_(3) ]^(3+)` contains total 36 electrons , i.e follows EAN rule