Cobalt (III) chloride forms several octahedral complexes with amonia. Which of the following will not give test for chloride ions with silver nitrate at `25^@C`?

Options

A. `[Co (NH_(3))_(3)]Cl_(3)`
B. `[Co(NH_(3))_(6)]Cl_(3)`
C. `[Co(NH_(3))_(4) Cl_(2) ]Cl`
D. `[Co)NH_(3))_(5)Cl]Cl_(2)`

Answer

A

Explanation

`[Co(NH_(3))_(6)]Cl_(3)to [Co(NH_(3))_(6)]^(3+)+3Cl^(-)`
`[Co(NH_(3))_(3)] to [Co(NH_(3))_(3)Cl_(3)]`
`[Co(NH_(3))_(4)Cl_(2)]Clto [Co(NH_(3))_(4)Cl_(2)]^(+)CL^(-)`
`[Co(NH_(3))_(5)Cl]Cl_(2) to [Co(NH_(3))_(5)Cl_(2)]^(2+)+2Cl^(-)`
`SO [Co (NH_(3))_(3)Cl_(3)]` does not give test for choride ions