Among the following ethers, which one will produce methyl alcohol on treatment with hot concentrated `HI`?

Options

A. `CH_(3)-CH_(2)-CH_(2)-CH_(2)-O-CH_(3)`
B. `CH_(3)-CH_(2)-underset(CH_(3))underset("| ")"CH"-O-CH_(3)`
C. `CH_(3)-overset(CH_(3))overset("| ")underset(CH_(3))underset("| ")"C "-O-CH_(3)`
D. `CH_(3)-underset(CH_(3))underset("| ")"CH"-CH_(2)-O-CH_(3)`

Answer

C

Explanation

The ether, which gives more stable carboncation, gives `CH_(3)OH` as one of the product with hot coccentrated `Hl`. The order of stability of carbocation is `3^(@)gt 2^(@) gt 1^(@)`
Thus, `{:(" "CH_(3)),(" |"),(CH_(3)-C-OCH_(3)),(" |"),(" "CH_(3)):}` gives `CH_(3)OH` as one of the products. The reaction proceeds as