In the following reaction the product E is
`underset(CHO)underset(|)(CHO)underset((ii)H^(+))overset((i)NaOH)toE`

Options

A. `underset(CHO)underset(|)(CH_(2)OH`
B. `underset(CO_(2)H)underset(|)(CHO)`
C. `underset(CO_(2)H)underset(|)(CH_(2)OH)`
D. `underset(CO_(2)H)underset(|)(CO_(2)H)`

Explanation

To solve the given problem, we need to analyze the reaction of glyceraldehyde (which has the structure CHO-CHO) when treated with sodium hydroxide (NaOH) followed by an acid (H+).

### Step-by-Step Solution:

1. **Identify the Structure**: The molecule in question is glyceraldehyde, which has two aldehyde groups. Its structure can be represented as:
\[ \text{CHO-CHO} \]

2. **Determine the Reaction Type**: Since glyceraldehyde does not have acidic alpha hydrogens (the hydrogens attached to the carbon adjacent to the carbonyl group), aldol condensation is not possible. Instead, we will consider the Cannizzaro reaction, which occurs in aldehydes without alpha hydrogens.

3. **Cannizzaro Reaction Mechanism**:
- In the presence of NaOH, one of the aldehyde groups will undergo nucleophilic attack by hydroxide ion (OH-), leading to the formation of an alkoxide intermediate.
- The other aldehyde group will be oxidized to a carboxylic acid while the first aldehyde is reduced to an alcohol.

4. **Formation of Intermediates**:
- The hydroxide ion attacks one of the carbonyl carbons, resulting in a tetrahedral intermediate where the carbonyl oxygen becomes negatively charged (alkoxide).
- This intermediate can then undergo a hydride transfer, where a hydride ion (H-) is transferred to the other carbonyl carbon, reducing it to an alcohol.

5. **Final Products**:
- After the hydride transfer, one aldehyde is converted to an alcohol (–CH2OH), and the other is oxidized to a carboxylic acid (–COOH).
- The final product E can be represented as:
\[ \text{CH}_2\text{OH-COOH} \]
or more formally as:
\[ \text{CH}_2\text{OH-CO}_2\text{H} \]

### Conclusion:
The product E formed from the reaction of glyceraldehyde with NaOH followed by H+ is:
\[ \text{CH}_2\text{OH-COOH} \]