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Compound 'A' (molecular formula C(3)H(8)...

Compound 'A' (molecular formula `C_(3)H_(8)O`) is treated with acidified potassium dichromate to form a product 'B' (molecular formula `C_(3)H_(6)O`)'B' forms a shining silver mirror on warming with ammoniacal silver nitrate 'B' when treated with an aqueous solution of `H_(2)NCONHNH_(2)` and sodium acetate gives a product 'C'. Identify the structure of 'C'

A

`CH_3CH_2CH=N NHCONH_2`

B

`(CH_3)_2C=N NHCONH_2`

C

`(CH_3)_2C= NCONHNH_2`

D

`CH_3CH_2CH=NCONHNH_2`

Text Solution

Verified by Experts

The correct Answer is:
A

(i)Aldehydes reduce ammoniacal `AgNO_3` to silver mirror .
(ii)`1^@` alcohol `overset"[O]"to ` aldehyde.
(iii)Aldehydes give addition product with ammonia derivative .
`therefore A (C_3H_8O)` is `1^@` alcohol, `B (C_3H_6O)` is aldehyde.
`underset"Propanol"undersetA(CH_3CH_2CH_2OH) underset(H_2SO_4)overset(K_2Cr_2O_7)to underset"Propanal"undersetB(CH_3CH_2CHO) overset(H_2NCONHNH_2)to CH_3CH_2CH undersetC=N NHCONH_2`
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Compound A (molecular formula C_(3)H_(8)O ) is treated with acidified potassium dichromate to form a product B (molecular formula C_(3)H_(6)O ) . B forms a shining silver mirror on warming with ammonical silver nitrate , B when treated with an aqueous solution of NH_(2)NHCONH_(2) and sodium acetate gives a product C . identify the structure of C .

Compound A (molecular formula C_(3)H_(8)O) is treated with acidified potassium dichromate to from a product B (molecular formula C_(3)H_(6)O . B forms shining silver mirror on warming with ammoniacal silver nitrate. Bwhen treated with an aqueous solution of H_(2)NCONHNH_(2) , HCI and solution acetate gives a productC. Identify the structure of C.

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