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In a compound C, H, N atoms are present ...

In a compound `C, H, N` atoms are present in `9:1:3.5` by weight. Molecular weight of compound is `108`. Its molecular formula is:

A

`C_2H_6N_2`

B

`C_3H_4N`

C

`C_6H_8N_2`

D

`C_9H_12N_3`

Text Solution

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The correct Answer is:
C
Find ratio of atoms, empirical formula, n and molecular formula.
Given, C : H : N = 9 : 1 : 3.5 (ratio of weights)
Mol. wt.= 108

`therefore` Empirical formula `=C_3H_4N`
Empirical formula wt. =12 x 3 +1 x 4 + 14 = 54
`n="mol. wt."/"empirical formula wt."=108/54=2`
Molecular formula = empirical formula x n
`=2 (C_3H_4N)`
`=C_6H_8N_2`
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