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Two boys P and Q are playing on a river ...

Two boys P and Q are playing on a river bank. P plans to swim across the river directly and come back. Q plans to swim downstream by a length equal to the width of the river and then come back. Both of them bet each other, claiming that the boy succeeding in less time will win. Assuming the swimming rate of both P and Q to the same, it can be concluded that

A

P wins

B

Q wins

C

A draw takes place

D

Nothing certain can be stated.

Text Solution

Verified by Experts

The correct Answer is:
A

a. Let d be the river width and u and v the speeds of water current.
for P, time taken
`t_1 = (2d)/(sqrt(v^2-u^2))` ……….(i)
For `Q`, time taken, `t_2 = d[1/(v+u) + 1/(v-u)]………(ii)`
Dividing Eq. (i) by (ii), we get
`t_1/t_2 = sqrt (1-(u/v)^2)lt1 rArr t_1ltt_2` .
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