Home
Class 11
PHYSICS
Two particles A and B are placed as show...

Two particles A and B are placed as shown in figure. The particle A, on the top of tower, is projected horizontally with a velocity u and particle B is projected along the surface towards the tower, simultaneously. If both particles meet each other, then the speed of projection of particles B is [ignore any friction]

A

`dsqrt(g/(2H)) - u`

B

`d sqrt(g/(2H))`

C

`dsqrt(g/(2H))+u`

D

u

Text Solution

Verified by Experts

The correct Answer is:
A
a. Time taken by particles to collide
`t = sqrt((2H)/(g))`
Then `u sqrt((2H)/(g))+Vsqrt((2H)/g) = d`
`rArr u + V = d sqrt(g/(2H)) or v = d sqrt(g/(2H)) - u `.
Promotional Banner

Topper's Solved these Questions

  • MISCELLANEOUS KINEMATICS

    CENGAGE PHYSICS|Exercise Multiple Correct Answer Type|26 Videos

  • MISCELLANEOUS KINEMATICS

    CENGAGE PHYSICS|Exercise Linked Comprehension Type|35 Videos

  • LINEAR AND ANGULAR SIMPLE HARMONIC MOTION

    CENGAGE PHYSICS|Exercise Multiple Correct Answer Type|9 Videos

  • MISCELLANEOUS VOLUME 2

    CENGAGE PHYSICS|Exercise INTEGER_TYPE|10 Videos

Similar Questions

Explore conceptually related problems

A particle is projected horizontally from a tower with velocity u towards east. Wind provides constant horizontal acceleration (g)/(2) towards west. If particle strikes the ground vertically the then :

Assertion Particle-1 is dropped from a tower and particle-2 is projected horizontal from the same tower. Then both the particles reach the ground simultaneously. Reason Both are particles strike the ground with different speeds.

Two particles A and B are projected simultaneously from a fixed point of the ground. Particle A is projected on a smooth horizontal surface with speed v, while particle B is projected in air with speed v, while particle B is projected in air with speed (2v)/(sqrt(3)) . If particle B hits the particle A, the angle of projection of B with the vertical is

Two particles are projected with speed 4 m//s and 3 m//s simultaneously from same point as shown in the figure. Then :

A particle is projected with velocity v at an angle theta aith horizontal. The average angle velocity of the particle from the point of projection to impact equals

Two particles A and B projected simultaneously from a point situated on a horizontal place. The particle A is projected vertically up with a velcity v_(A) while the particle B is projected up at an angle 30^(@) with horizontal with velocity v_(B) . After 5s the particles were observed moving mutually perpendicular to each other. The velocity of projection of the particle v_(A) and v_(B) respectively are:

A particle is projected vertically upwards and t second after another particle is projected upwards with the same initial velocity. Prove that the particles will meet after a lapse of ((t)/(2)+(u)/(g)) time from the instant of projection of the first particle.

A particle is projected along an inclined plane as shown in figure. What is the speed of the particle when it collides at point A ? (g = 10 m//s)