Home
Class 11
PHYSICS
A ball rolls off the top of a staircase ...

A ball rolls off the top of a staircase with a horizontal velocity `u m//s`. If the steps are h meter high and b meter wide, the ball will hit the edge of the nth steps, if:

A

9

B

10

C

11

D

12

Text Solution

Verified by Experts

The correct Answer is:
A
a. `0.2n = 1/2 "gt"^2` or `t = sqrt((2 xx 0.2n)/(g))`
` 0.3 n = ut = 4.5 sqrt((2xx0.2n)/(g))`
` rArr n = 9`
Promotional Banner

Topper's Solved these Questions

  • MISCELLANEOUS KINEMATICS

    CENGAGE PHYSICS|Exercise Multiple Correct Answer Type|26 Videos

  • MISCELLANEOUS KINEMATICS

    CENGAGE PHYSICS|Exercise Linked Comprehension Type|35 Videos

  • LINEAR AND ANGULAR SIMPLE HARMONIC MOTION

    CENGAGE PHYSICS|Exercise Multiple Correct Answer Type|9 Videos

  • MISCELLANEOUS VOLUME 2

    CENGAGE PHYSICS|Exercise INTEGER_TYPE|10 Videos

Similar Questions

Explore conceptually related problems

A ball rolls off top of a staircase with a horizontal velocity u m s^-1 . If the steps are h metre high and b mere wide, the ball will just hit the edge of n th step. Find the value of n .

A ball rolls off top of a stair case with horizontal velocity u (m)/(s) if the steps are h meter high and b meter wide, the ball will just hit the edge of n^(th) step. Then value of n is:

Velocity at a general point P(x, y) for a horizontal projectile motion is given by v=sqrt((v_("x")^(2)+v_("y")"^(2))),tan alpha=(v_(y))/(v_(x)) alpha is angle made by v with horizontal in clockwise direction Trajectory equation for a horizontal projectile motion is given by x=v_(x)t=ut y=- (1//2)"gt"^(2) eliminating t, we get y=-(1//2)(gx^(2))/(u^(2) A ball rolls off top of a stair way with a horizontal velocity u m//s. If the steps are h m high and b meters wide, the ball will just hit the edge of nth step if n^(th) equals to

A ball rolls off the top of a stairway with a constant horizontal velocity u. If the steps are h metre high and w metre wide, show that the ball will just hit the edge of nth step if n = 2hu^(2)/gw^(2)

A ball rolls off the top of a stairway with a horizontal velocity u . If the height and width of steps are b and h respectively and the ball hits the edge of n^(th) step, then n is equal to

A ball rolls of the top fi a strair way with horizonntal velocity of magnitude 1. 8 ms^(-1) . The steps are 0.20 m high and 0.02 m wide , Which step will the ball it first ? ( g = 10 m//s^@) .

A ball rolls from the edge of the top step of a stair case with horizontal speed 5ms^(-1) .Each step is of 2m high and 1m width.The ball hits nth step then 'n' is (g=10m/s^(2))

A small rolls of the top of a stairway horizontally with a velocity of 4.5 ms^(-1) . Each step is 0.2 m high and 0.3 m wide. If g is 10ms^(-2) , then the ball will strike the nth step where n is equal to (assume ball strike at the edge of the step).

[" A staircase has steps each of "],[" height "20cm" and width "40cm" .A "],[" ball rolls off the top of the "],[" staircase horizontally with "],[" velocity "5m/s" .The ball hits the "],[" nth step from the top at the first "],[" bounce,then "n=..........." (take "],[g=10ms-2)]